8.39 grams ##HCl## will react with 5.00 grams of ##MnO_2##
##4HCl + MnO_2 -> 2H_2O + MnCl_2 + Cl_2##
For this reaction determine the mass of HCl that will react with
5.00 grams of manganese dioxide.
This is a basic problem of mass to mass conversions.
## grams -> moles -> moles -> grams##
Mass of ##MnO_2 = 54.94 + 2(15.99) = 86.92 g MnO_2##
Mass of ##HCl = 1.01 + 35.45 = 36.46 g HCl##
##5.00 cancel(g MnO_2) xx (1 cancel(mol MnO_2))/(86.92 cancel(g MnO_2)) xx (4 cancel(mol HCl))/(1cancel(mol MnO_2)) xx 36.46 g HCl/(1 cancel(mol HCl))##
The middle conversion factor is to mole ratio from the balance chemical equation of ##4 mol HCl## for ##1 mol MnO_2##
##((5.00) (4) (36.46))/(86.92)##
##8.39 grams HCl##
Here is a gram to gram video explanation.
http://bit.ly/1kljEVR